Comments on: Asymmetric encryption / public key encryption / RSA https://www.ticklishtechs.net/2008/06/17/asymmetric-encryption-public-key-encryption-rsa/ a mostly .NET but also some other cool techs blog Thu, 13 Aug 2020 18:46:43 +0000 hourly 1 https://wordpress.org/?v=5.7.11 By: Rafael https://www.ticklishtechs.net/2008/06/17/asymmetric-encryption-public-key-encryption-rsa/comment-page-1/#comment-6272 Thu, 13 Aug 2009 20:30:44 +0000 http://www.ticklishtechs.net/2008/06/17/asymmetric-encryption-public-key-encryption-rsa/#comment-6272 Nice article. A description of a method that allows both hashing and decryption of asymmetric passwords you can find here http://www.developers-blog.org/blog/default/2009/07/05/Public-Key-based-asymmetic-password-hashing.

]]> By: Jan https://www.ticklishtechs.net/2008/06/17/asymmetric-encryption-public-key-encryption-rsa/comment-page-1/#comment-5849 Wed, 08 Jul 2009 09:36:44 +0000 http://www.ticklishtechs.net/2008/06/17/asymmetric-encryption-public-key-encryption-rsa/#comment-5849 Hi Bob,
based on how you approach the math problem, I find it amazing taking to consider that I am not a math whiz. Anyway, I have a math problem and hoping if you could shed light on it. Just try. Actually this concerns hexadecimal values.

Consider this,
I have a string of hex values, I receive from a particular device as stated below:

#1 Data:
20 02 1e 00 01 3f 01 1d 01 00 02 3f 52 00 01 00 02 3f 52 6d 20 33 00 00 42 61 74 68 00 00 00 00 01 03 03 03 29 3f 09 3f 02 00 08

#2 Data:
20 02 1e 00 01 3f 01 11 01 00 02 3f 52 00 01 00 02 3f 52 6d 20 33 00 00 42 61 74 68 00 00 00 00 01 03 03 03 29 3f 09 3f 02 00 08

#3 Data:
20 02 1e 00 01 3f 01 15 01 00 02 3f 52 00 01 00 02 3f 52 6d 20 33 00 00 42 61 74 68 00 00 00 00 01 03 03 03 29 3f 09 3f 02 00 08

Now using this hex value below, would I conclude that the #1 Data: is identical to my last hex value below:

last hex value:
20 02 1e 00 01 3f 01 18 01 00 02 3f 52 00 01 00 02 3f 52 6d 20 33 00 00 42 61 74 68 00 00 00 00 01 03 03 03 29 3f 09 3f 02 00 08

You may or may not reply to me but I was hoping if you found something you could reply me back by any chance..

Thanks

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